6. Вычислить: д) \(\frac{1}{2} - \frac{9}{25}\) е) \(\frac{14}{25} + \frac{3}{2}\) ж) \(\frac{11}{5} + \frac{13}{4}\)

Решение:

1. д) \(\frac{1}{2} - \frac{9}{25} = \frac{1 × 25}{2 × 25} - \frac{9 × 2}{25 × 2} = \frac{25}{50} - \frac{18}{50} = \frac{25-18}{50} = \frac{7}{50}\)
2. е) \(\frac{14}{25} + \frac{3}{2} = \frac{14 × 2}{25 × 2} + \frac{3 × 25}{2 × 25} = \frac{28}{50} + \frac{75}{50} = \frac{28+75}{50} = \frac{103}{50}\)
3. ж) \(\frac{11}{5} + \frac{13}{4} = \frac{11 × 4}{5 × 4} + \frac{13 × 5}{4 × 5} = \frac{44}{20} + \frac{65}{20} = \frac{44+65}{20} = \frac{109}{20}\)

Ответ: д) \(\frac{7}{50}\), е) \(\frac{103}{50}\), ж) \(\frac{109}{20}\).