Вопрос:

6 : 18/19 + 2 1/6 · |7/18 − 3 3/104| =

Ответ:

\(6 : \frac{18}{19}=6\cdot\frac{19}{18}=\frac{19}{3}\).

\(3\frac{3}{104}=\frac{315}{104}\), а \(\frac{7}{18}=\frac{364}{936}\).

\(\left|\frac{7}{18}−3\frac{3}{104}\right|=\left|\frac{364}{936}−\frac{2835}{936}\right|=\frac{2471}{936}\).

\(2\frac{1}{6}\cdot\frac{2471}{936}=\frac{13}{6}\cdot\frac{2471}{936}=\frac{32123}{5616}\).

\(\frac{19}{3}+\frac{32123}{5616}=\frac{67691}{5616}\).

Ответ: \(\frac{67691}{5616}\)