6) \(10\sqrt3-4\sqrt{48}+\sqrt{27}\)

\[\sqrt{48}=4\sqrt3,\quad \sqrt{27}=3\sqrt3.\]

\[10\sqrt3-4\sqrt{48}+\sqrt{27}=10\sqrt3-16\sqrt3+3\sqrt3=-3\sqrt3.\]

Ответ: \(-3\sqrt3\).