Ответ:
Преобразуем смешанные числа:
\(1\dfrac{1}{4}=\dfrac{5}{4}\), \(3\dfrac{3}{7}=\dfrac{24}{7}\), \(10\dfrac{1}{5}=\dfrac{51}{5}\).
\(\left(\dfrac{5}{4}\cdot\dfrac{2}{5}+\dfrac{24}{7}:\dfrac{9}{14}\right):\dfrac{5}{12}-\dfrac{51}{5}\)
\(=\left(\dfrac{1}{2}+\dfrac{24}{7}\cdot\dfrac{14}{9}\right):\dfrac{5}{12}-\dfrac{51}{5}\)
\(=\left(\dfrac{1}{2}+\dfrac{16}{3}\right):\dfrac{5}{12}-\dfrac{51}{5}=\dfrac{35}{6}\cdot\dfrac{12}{5}-\dfrac{51}{5}\)
\(=14-\dfrac{51}{5}=\dfrac{70}{5}-\dfrac{51}{5}=\dfrac{19}{5}=3\dfrac{4}{5}\).
Ответ: \(3\dfrac{4}{5}\).
