\[ \frac{3}{5} + \frac{2}{5} = \frac{3+2}{5} = \frac{5}{5} = 1 \]
\[ 1 - \frac{4}{7} = \frac{7}{7} - \frac{4}{7} = \frac{7-4}{7} = \frac{3}{7} \]
\[ \frac{3}{7} - \frac{3}{7} = 0 \]
\[ 3 \frac{2}{7} + \frac{3}{7} = 3 + (\frac{2}{7} + \frac{3}{7}) = 3 + \frac{5}{7} = 3 \frac{5}{7} \]
\[ 3 \frac{5}{7} - 2 \frac{1}{7} = (3-2) + (\frac{5}{7} - \frac{1}{7}) = 1 + \frac{4}{7} = 1 \frac{4}{7} \]
\[ 1 \frac{4}{7} + 4 \frac{3}{7} = (1+4) + (\frac{4}{7} + \frac{3}{7}) = 5 + \frac{7}{7} = 5 + 1 = 6 \]
\[ 6 - 1 \frac{1}{2} = (5 + \frac{2}{2}) - 1 \frac{1}{2} = 5 \frac{2}{2} - 1 \frac{1}{2} = (5-1) + (\frac{2}{2} - \frac{1}{2}) = 4 + \frac{1}{2} = 4 \frac{1}{2} \]
\[ 4 \frac{1}{2} + 5 = (4+5) + \frac{1}{2} = 9 \frac{1}{2} \]
Ответ: 1; 3/7; 0; 3 5/7; 1 4/7; 6; 4 1/2; 9 1/2.