487. 1) (-²/₅ a³x³y⁸) : (-¹⁄₂ a³xy⁹); 2) (-³/₄ a⁵b³c) : (1¹⁄₂ a²b²c)

Решение:

1. \( \left(-\frac{2}{5}a^3x^3y^8\right) : \left(-\frac{1}{2}a^3xy^9\right) = \frac{-\frac{2}{5}a^3x^3y^8}{-\frac{1}{2}a^3xy^9} = \frac{2}{5} \cdot \frac{2}{1} a^{3-3} x^{3-1} y^{8-9} = \frac{4}{5} a^0 x^2 y^{-1} = \frac{4x^2}{5y} \)
2. \( \left(-\frac{3}{4}a^5b^3c\right) : \left(1\frac{1}{2}a^2b^2c\right) = \left(-\frac{3}{4}a^5b^3c\right) : \left(\frac{3}{2}a^2b^2c\right) = \frac{-\frac{3}{4}a^5b^3c}{\frac{3}{2}a^2b^2c} = -\frac{3}{4} \cdot \frac{2}{3} a^{5-2} b^{3-2} c^{1-1} = -\frac{1}{2} a^3 b^1 c^0 = -\frac{1}{2}a^3b \)

Ответ: ⁴ˣ²/₅ʸ; -½a³b.