This question asks to solve two equations and then perform a multiplication.
Equation 1: x + 3 = 27
To solve for x, subtract 3 from both sides of the equation:
x + 3 - 3 = 27 - 3
x = 24
Equation 2: x - 3 = 27
To solve for x, add 3 to both sides of the equation:
x - 3 + 3 = 27 + 3
x = 30
Multiplication: x ⋅ 3
Now we need to determine which value of 'x' to use. The question presents 'x⋅3=?' after the two equations, implying we should use the value of 'x' from the second equation as it directly precedes the multiplication. Therefore, we use x = 30.
30 ⋅ 3 = 90
Ответ: x = 24, x = 30, 90