Ответ:

А

  1. \(x=\frac{5}{6}-\frac{1}{3}=\frac{1}{2}\).
  2. \(b=\frac{1}{3}:\frac{1}{9}=3\).
  3. \(b=\frac{1}{4}+\frac{1}{8}=\frac{3}{8}\).
  4. \(y=\frac{1}{2}-\frac{1}{3}=\frac{1}{6}\).
  5. \(c=\frac{1}{5}:4=\frac{1}{20}\).

Б

  1. \(x=\frac{1}{5}-\frac{1}{10}=\frac{1}{10}\).
  2. \(y=\frac{5}{6}+\frac{1}{12}=\frac{11}{12}\).
  3. \(a=\frac{7}{12}-\frac{1}{6}=\frac{5}{12}\).
  4. \(b=\frac{1}{6}\cdot\frac{1}{5}=\frac{1}{30}\).
  5. \(4:b=\frac{1}{4}\), значит \(b=4:\frac{1}{4}=16\).

В

  1. \(c=\frac{7}{10}-\frac{1}{5}=\frac{1}{2}\).
  2. \(b=\frac{1}{6}+\frac{1}{6}=\frac{1}{3}\).
  3. \(a=\frac{1}{2}-\frac{1}{8}=\frac{3}{8}\).
  4. \(x=\frac{1}{5}:\frac{1}{3}=\frac{3}{5}\).
  5. \(y=\frac{1}{2}:5=\frac{1}{10}\).

Г

  1. \(y=\frac{1}{10}\cdot8=\frac{4}{5}\).
  2. \(y=\frac{2}{7}\cdot3=\frac{6}{7}\).
  3. \(x=\frac{1}{2}-\frac{1}{6}=\frac{1}{3}\).
  4. \(a=\frac{1}{3}+\frac{4}{9}=\frac{7}{9}\).
  5. \(c=\frac{1}{3}+\frac{1}{6}=\frac{1}{2}\).