Ответ:
А
- \(x=\frac{5}{6}-\frac{1}{3}=\frac{1}{2}\).
- \(b=\frac{1}{3}:\frac{1}{9}=3\).
- \(b=\frac{1}{4}+\frac{1}{8}=\frac{3}{8}\).
- \(y=\frac{1}{2}-\frac{1}{3}=\frac{1}{6}\).
- \(c=\frac{1}{5}:4=\frac{1}{20}\).
Б
- \(x=\frac{1}{5}-\frac{1}{10}=\frac{1}{10}\).
- \(y=\frac{5}{6}+\frac{1}{12}=\frac{11}{12}\).
- \(a=\frac{7}{12}-\frac{1}{6}=\frac{5}{12}\).
- \(b=\frac{1}{6}\cdot\frac{1}{5}=\frac{1}{30}\).
- \(4:b=\frac{1}{4}\), значит \(b=4:\frac{1}{4}=16\).
В
- \(c=\frac{7}{10}-\frac{1}{5}=\frac{1}{2}\).
- \(b=\frac{1}{6}+\frac{1}{6}=\frac{1}{3}\).
- \(a=\frac{1}{2}-\frac{1}{8}=\frac{3}{8}\).
- \(x=\frac{1}{5}:\frac{1}{3}=\frac{3}{5}\).
- \(y=\frac{1}{2}:5=\frac{1}{10}\).
Г
- \(y=\frac{1}{10}\cdot8=\frac{4}{5}\).
- \(y=\frac{2}{7}\cdot3=\frac{6}{7}\).
- \(x=\frac{1}{2}-\frac{1}{6}=\frac{1}{3}\).
- \(a=\frac{1}{3}+\frac{4}{9}=\frac{7}{9}\).
- \(c=\frac{1}{3}+\frac{1}{6}=\frac{1}{2}\).
