$$\frac{2}{2+\sqrt{3}}+2\sqrt{3}$$
$$= \frac{2(2-\sqrt{3})}{(2+\sqrt{3})(2-\sqrt{3})} + 2\sqrt{3}$$
$$= \frac{2(2-\sqrt{3})}{4-3} + 2\sqrt{3} = 2(2-\sqrt{3}) + 2\sqrt{3} = 4-2\sqrt{3}+2\sqrt{3} = 4$$