Решение:
- 30. \(\frac{x}{8} + 11 = 0\)
\[ \frac{x}{8} = -11 \]
\[ x = -11 \times 8 = -88 \] - 31. \(\frac{x}{4} = \frac{3}{2} + \frac{x}{8}\)
Умножим обе части на 8:
\[ 8 \times \frac{x}{4} = 8 \times \frac{3}{2} + 8 \times \frac{x}{8} \]
\[ 2x = 12 + x \]
\[ 2x - x = 12 \]
\[ x = 12 \] - 32. \(\frac{x}{16} + 2 = \frac{x}{4}\)
Умножим обе части на 16:
\[ 16 \times \frac{x}{16} + 16 \times 2 = 16 \times \frac{x}{4} \]
\[ x + 32 = 4x \]
\[ 32 = 4x - x \]
\[ 32 = 3x \]
\[ x = \frac{32}{3} \]
Ответ: 30) \(x = -88\); 31) \(x = 12\); 32) \(x = \frac{32}{3}\)