Вопрос:

28. Представьте смешанные числа в виде неправильных дробей.

Ответ:

Для преобразования смешанного числа в неправильную дробь, умножаем целую часть на знаменатель дробной части и прибавляем числитель дробной части. Полученное число будет числителем новой дроби, а знаменатель остается прежним.

* \(2 \frac{7}{12} = \frac{2 \cdot 12 + 7}{12} = \frac{24 + 7}{12} = \frac{31}{12}\)
* \(4 \frac{4}{11} = \frac{4 \cdot 11 + 4}{11} = \frac{44 + 4}{11} = \frac{48}{11}\)
* \(4 \frac{3}{10} = \frac{4 \cdot 10 + 3}{10} = \frac{40 + 3}{10} = \frac{43}{10}\)
* \(2 \frac{5}{9} = \frac{2 \cdot 9 + 5}{9} = \frac{18 + 5}{9} = \frac{23}{9}\)
* \(4 \frac{5}{8} = \frac{4 \cdot 8 + 5}{8} = \frac{32 + 5}{8} = \frac{37}{8}\)
* \(1 \frac{19}{25} = \frac{1 \cdot 25 + 19}{25} = \frac{25 + 19}{25} = \frac{44}{25}\)
* \(3 \frac{4}{9} = \frac{3 \cdot 9 + 4}{9} = \frac{27 + 4}{9} = \frac{31}{9}\)
* \(5 \frac{1}{3} = \frac{5 \cdot 3 + 1}{3} = \frac{15 + 1}{3} = \frac{16}{3}\)
* \(6 \frac{2}{5} = \frac{6 \cdot 5 + 2}{5} = \frac{30 + 2}{5} = \frac{32}{5}\)
* \(3 \frac{2}{5} = \frac{3 \cdot 5 + 2}{5} = \frac{15 + 2}{5} = \frac{17}{5}\)
* \(1 \frac{5}{6} = \frac{1 \cdot 6 + 5}{6} = \frac{6 + 5}{6} = \frac{11}{6}\)
* \(3 \frac{8}{11} = \frac{3 \cdot 11 + 8}{11} = \frac{33 + 8}{11} = \frac{41}{11}\)
* \(7 \frac{3}{7} = \frac{7 \cdot 7 + 3}{7} = \frac{49 + 3}{7} = \frac{52}{7}\)
* \(17 \frac{2}{3} = \frac{17 \cdot 3 + 2}{3} = \frac{51 + 2}{3} = \frac{53}{3}\)
* \(5 \frac{2}{5} = \frac{5 \cdot 5 + 2}{5} = \frac{25 + 2}{5} = \frac{27}{5}\)
* \(1 \frac{51}{53} = \frac{1 \cdot 53 + 51}{53} = \frac{53 + 51}{53} = \frac{104}{53}\)
* \(2 \frac{6}{13} = \frac{2 \cdot 13 + 6}{13} = \frac{26 + 6}{13} = \frac{32}{13}\)
* \(3 \frac{5}{12} = \frac{3 \cdot 12 + 5}{12} = \frac{36 + 5}{12} = \frac{41}{12}\)
* \(7 \frac{1}{5} = \frac{7 \cdot 5 + 1}{5} = \frac{35 + 1}{5} = \frac{36}{5}\)
* \(3 \frac{3}{4} = \frac{3 \cdot 4 + 3}{4} = \frac{12 + 3}{4} = \frac{15}{4}\)
* \(2 \frac{1}{4} = \frac{2 \cdot 4 + 1}{4} = \frac{8 + 1}{4} = \frac{9}{4}\)
* \(2 \frac{8}{9} = \frac{2 \cdot 9 + 8}{9} = \frac{18 + 8}{9} = \frac{26}{9}\)
* \(29 \frac{1}{2} = \frac{29 \cdot 2 + 1}{2} = \frac{58 + 1}{2} = \frac{59}{2}\)
* \(5 \frac{5}{11} = \frac{5 \cdot 11 + 5}{11} = \frac{55 + 5}{11} = \frac{60}{11}\)
* \(10 \frac{2}{3} = \frac{10 \cdot 3 + 2}{3} = \frac{30 + 2}{3} = \frac{32}{3}\)
* \(7 \frac{4}{5} = \frac{7 \cdot 5 + 4}{5} = \frac{35 + 4}{5} = \frac{39}{5}\)
* \(7 \frac{5}{8} = \frac{7 \cdot 8 + 5}{8} = \frac{56 + 5}{8} = \frac{61}{8}\)
* \(9 \frac{3}{4} = \frac{9 \cdot 4 + 3}{4} = \frac{36 + 3}{4} = \frac{39}{4}\)
* \(6 \frac{2}{7} = \frac{6 \cdot 7 + 2}{7} = \frac{42 + 2}{7} = \frac{44}{7}\)
* \(3 \frac{5}{6} = \frac{3 \cdot 6 + 5}{6} = \frac{18 + 5}{6} = \frac{23}{6}\)
* \(11 \frac{3}{5} = \frac{11 \cdot 5 + 3}{5} = \frac{55 + 3}{5} = \frac{58}{5}\)
* \(13 \frac{4}{9} = \frac{13 \cdot 9 + 4}{9} = \frac{117 + 4}{9} = \frac{121}{9}\)
* \(5 \frac{7}{8} = \frac{5 \cdot 8 + 7}{8} = \frac{40 + 7}{8} = \frac{47}{8}\)
* \(3 \frac{1}{9} = \frac{3 \cdot 9 + 1}{9} = \frac{27 + 1}{9} = \frac{28}{9}\)
* \(13 \frac{1}{2} = \frac{13 \cdot 2 + 1}{2} = \frac{26 + 1}{2} = \frac{27}{2}\)
* \(4 \frac{5}{7} = \frac{4 \cdot 7 + 5}{7} = \frac{28 + 5}{7} = \frac{33}{7}\)