Ответ:
Приводим дроби к общему знаменателю, затем выполняем сложение или вычитание и сокращаем результат.
А:
- \(\frac{1}{3}+\frac{1}{6}=\frac{2}{6}+\frac{1}{6}=\frac{1}{2}\)
- \(\frac{1}{2}+\frac{1}{3}=\frac{3}{6}+\frac{2}{6}=\frac{5}{6}\)
- \(\frac{3}{5}-\frac{1}{10}=\frac{6}{10}-\frac{1}{10}=\frac{1}{2}\)
- \(\frac{1}{12}+\frac{5}{6}=\frac{1}{12}+\frac{10}{12}=\frac{11}{12}\)
- \(\frac{1}{3}+\frac{1}{4}=\frac{4}{12}+\frac{3}{12}=\frac{7}{12}\)
- \(\frac{1}{3}+\frac{2}{5}=\frac{5}{15}+\frac{6}{15}=\frac{11}{15}\)
- \(\frac{1}{2}-\frac{1}{4}=\frac{1}{4}\)
- \(\frac{8}{7}-1=\frac{8}{7}-\frac{7}{7}=\frac{1}{7}\)
- \(\frac{1}{4}-\frac{1}{5}=\frac{5}{20}-\frac{4}{20}=\frac{1}{20}\)
- \(\frac{1}{2}+\frac{3}{7}=\frac{7}{14}+\frac{6}{14}=\frac{13}{14}\)
- \(\frac{3}{4}-\frac{1}{8}=\frac{6}{8}-\frac{1}{8}=\frac{5}{8}\)
- \(\frac{1}{6}+\frac{1}{6}=\frac{1}{3}\)
- \(\frac{4}{15}+\frac{2}{5}=\frac{4}{15}+\frac{6}{15}=\frac{2}{3}\)
- \(\frac{7}{10}-\frac{1}{2}=\frac{7}{10}-\frac{5}{10}=\frac{1}{5}\)
- \(\frac{1}{3}-\frac{1}{4}=\frac{4}{12}-\frac{3}{12}=\frac{1}{12}\)
Б: \(\frac{1}{6};\ \frac{9}{10};\ \frac{1}{9};\ \frac{9}{20};\ \frac{2}{3};\ \frac{7}{12};\ \frac{4}{15};\ \frac{1}{30};\ \frac{3}{4};\ \frac{1}{6};\ \frac{11}{14};\ \frac{1}{6};\ \frac{7}{8};\ \frac{1}{4};\ \frac{7}{10}\).
В: \(\frac{2}{15};\ \frac{55}{54};\ \frac{1}{42};\ \frac{11}{48};\ \frac{1}{54};\ \frac{1}{75};\ \frac{7}{15};\ \frac{1}{30};\ \frac{29}{40};\ \frac{1}{42};\ \frac{46}{45};\ \frac{5}{7};\ \frac{1}{30};\ \frac{1}{8};\ \frac{7}{6}\).
