Ответ:
а)
\(5\frac{2}{5}=\frac{27}{5}\), \(1\frac{1}{9}=\frac{10}{9}\), \(4\frac{4}{7}=\frac{32}{7}\), \(1\frac{3}{4}=\frac{7}{4}\).
\(\frac{27}{5}\cdot\frac{10}{9}-\frac{32}{7}\cdot\frac{7}{4}=6-8=-2\).
б)
\(7\frac{1}{3}=\frac{22}{3}\), \(1\frac{2}{9}=\frac{11}{9}\), \(4\frac{8}{9}=\frac{44}{9}\).
\(\frac{22}{3}:\frac{11}{9}+\frac{44}{9}\cdot\frac{9}{11}=6+4=10\).
в)
\(2\frac{1}{3}=\frac{7}{3}\), \(17\frac{1}{3}=\frac{52}{3}\).
\(\frac{52}{3}:13=\frac{4}{3}\), поэтому
\(\frac{7}{3}:\left(2-\frac{4}{3}\right)=\frac{7}{3}:\frac{2}{3}=\frac{7}{2}=3\frac{1}{2}\).
г)
\(3\frac{3}{8}=\frac{27}{8}\), \(1\frac{7}{9}=\frac{16}{9}\).
\(\left(\frac{27}{8}\cdot\frac{16}{9}-3\right):\frac{3}{5}=(6-3):\frac{3}{5}=3\cdot\frac{5}{3}=5\).
Ответ: а) −2; б) 10; в) 3 1/2; г) 5.
