а) \( 2\frac{2}{5} + 7\frac{3}{10} = 2\frac{4}{10} + 7\frac{3}{10} = (2+7) + (\frac{4}{10} + \frac{3}{10}) = 9 + \frac{7}{10} = 9\frac{7}{10} \)
б) \( 6\frac{7}{8} + 3\frac{5}{12} = 6\frac{21}{24} + 3\frac{10}{24} = (6+3) + (\frac{21}{24} + \frac{10}{24}) = 9 + \frac{31}{24} = 9 + 1\frac{7}{24} = 10\frac{7}{24} \)