Ответ:
\(\frac{11}{30}-\frac{4}{15}+\frac{1}{20}=\frac{22}{60}-\frac{16}{60}+\frac{3}{60}=\frac{9}{60}=\frac{3}{20}\).
\(9-5\frac{7}{11}=8\frac{11}{11}-5\frac{7}{11}=3\frac{4}{11}\).
\(5\frac{4}{9}+2\frac{5}{72}=7+\frac{32}{72}+\frac{5}{72}=7\frac{37}{72}\).
\(7\frac{15}{16}+2\frac{11}{24}=9+\frac{45}{48}+\frac{22}{48}=9\frac{67}{48}=10\frac{19}{48}\).
\(1\frac{1}{5}-4\frac{7}{10}=1\frac{2}{10}-4\frac{7}{10}=-3\frac{5}{10}=-3\frac{1}{2}\).
Ответ: а) \(\frac{3}{20}\); б) \(3\frac{4}{11}\); в) \(7\frac{37}{72}\); г) \(10\frac{19}{48}\); д) \(-3\frac{1}{2}\).
