Ответ:
\(2\frac{2}{35}\cdot\frac79+1\frac5{22}:\frac9{11}-1{,}8=\frac{72}{35}\cdot\frac79+\frac{27}{22}\cdot\frac{11}{9}-1{,}8=\frac85+\frac32-1{,}8=1{,}6+1{,}5-1{,}8=1{,}3\).
Ответ: \(1{,}3\).
\(2\frac{2}{35}\cdot\frac79+1\frac5{22}:\frac9{11}-1{,}8=\frac{72}{35}\cdot\frac79+\frac{27}{22}\cdot\frac{11}{9}-1{,}8=\frac85+\frac32-1{,}8=1{,}6+1{,}5-1{,}8=1{,}3\).
Ответ: \(1{,}3\).