2. a) 2(2 + y) = 19 - 3y; 6) -3(3b + 1) - 12 = 12; в) -2(2-5x) = 2(x - 3) -5; г) - 4,92у - (0,08y + 5,12) = - 0,88 - у.

Решение:

1. а)\[ 2(2 + y) = 19 - 3y \]\[ 4 + 2y = 19 - 3y \]\[ 2y + 3y = 19 - 4 \]\[ 5y = 15 \]\[ y = \frac{15}{5} \]\[ y = 3 \]
2. б)\[ -3(3b + 1) - 12 = 12 \]\[ -9b - 3 - 12 = 12 \]\[ -9b - 15 = 12 \]\[ -9b = 12 + 15 \]\[ -9b = 27 \]\[ b = \frac{27}{-9} \]\[ b = -3 \]
3. в)\[ -2(2 - 5x) = 2(x - 3) - 5 \]\[ -4 + 10x = 2x - 6 - 5 \]\[ -4 + 10x = 2x - 11 \]\[ 10x - 2x = -11 + 4 \]\[ 8x = -7 \]\[ x = -\frac{7}{8} \]
4. г)\[ -4,92y - (0,08y + 5,12) = -0,88 - y \]\[ -4,92y - 0,08y - 5,12 = -0,88 - y \]\[ -5y - 5,12 = -0,88 - y \]\[ -5y + y = -0,88 + 5,12 \]\[ -4y = 4,24 \]\[ y = \frac{4,24}{-4} \]\[ y = -1,06 \]

Ответ: а) 3; б) -3; в) -7/8; г) -1,06.