Вопрос:

2.9. 1) \(\frac{x}{3}-\frac{1}{6}=\frac{1}{2}\); 3) \(\frac{4x}{5}-\frac{1}{6}=-3\frac{1}{2}\); 5) \(2-\frac{x}{4}=-1,5\).

Ответ:

  1. \[\frac{x}{3}-\frac{1}{6}=\frac{1}{2}\]

    \[\frac{x}{3}=\frac{1}{2}+\frac{1}{6}=\frac{3}{6}+\frac{1}{6}=\frac{4}{6}=\frac{2}{3}\]

    \[x=2\]

    Ответ: \(x=2\).

  2. \[\frac{4x}{5}-\frac{1}{6}=-3\frac{1}{2}=-\frac{7}{2}\]

    \[\frac{4x}{5}=-\frac{7}{2}+\frac{1}{6}=-\frac{21}{6}+\frac{1}{6}=-\frac{20}{6}=-\frac{10}{3}\]

    \[x=-\frac{10}{3}\cdot\frac{5}{4}=-\frac{25}{6}\]

    Ответ: \(x=-\frac{25}{6}\).

  3. \[2-\frac{x}{4}=-1.5\]

    \[-\frac{x}{4}=-1.5-2=-3.5\]

    \[x=14\]

    Ответ: \(x=14\).