Контрольные задания >
13) \frac{27}{28} + \frac{4}{28} = ?
14) 4\frac{7}{20} + 2\frac{17}{20} = ?
15) \frac{23}{26} + \frac{11}{26} = ?
16) 3\frac{10}{13} + 5\frac{11}{13} = ?
17) \frac{8}{11} + \frac{5}{11} = ?
18) 7\frac{3}{10} + 3\frac{7}{10} = ?
19) 7\frac{8}{19} + 1\frac{13}{19} = ?
20) \frac{9}{14} + 5\frac{11}{14} = ?
21) 7\frac{1}{8} + \frac{3}{8} = ?
22) 31\frac{1}{9} + 12\frac{8}{9} = ?
23) 9\frac{7}{12} + \frac{1}{12} = ?
24) 17\frac{9}{10} + 50\frac{7}{10} = ? Вопрос:
13) \frac{27}{28} + \frac{4}{28} = ?
14) 4\frac{7}{20} + 2\frac{17}{20} = ?
15) \frac{23}{26} + \frac{11}{26} = ?
16) 3\frac{10}{13} + 5\frac{11}{13} = ?
17) \frac{8}{11} + \frac{5}{11} = ?
18) 7\frac{3}{10} + 3\frac{7}{10} = ?
19) 7\frac{8}{19} + 1\frac{13}{19} = ?
20) \frac{9}{14} + 5\frac{11}{14} = ?
21) 7\frac{1}{8} + \frac{3}{8} = ?
22) 31\frac{1}{9} + 12\frac{8}{9} = ?
23) 9\frac{7}{12} + \frac{1}{12} = ?
24) 17\frac{9}{10} + 50\frac{7}{10} = ?
Смотреть решения всех заданий с листаОтвет:
Решение:
- 13) \( \frac{27}{28} + \frac{4}{28} = \frac{27+4}{28} = \frac{31}{28} = 1\frac{3}{28} \)
- 14) \( 4\frac{7}{20} + 2\frac{17}{20} = (4+2) + \frac{7+17}{20} = 6 + \frac{24}{20} = 6 + 1\frac{4}{20} = 7\frac{4}{20} = 7\frac{1}{5} \)
- 15) \( \frac{23}{26} + \frac{11}{26} = \frac{23+11}{26} = \frac{34}{26} = 1\frac{8}{26} = 1\frac{4}{13} \)
- 16) \( 3\frac{10}{13} + 5\frac{11}{13} = (3+5) + \frac{10+11}{13} = 8 + \frac{21}{13} = 8 + 1\frac{8}{13} = 9\frac{8}{13} \)
- 17) \( \frac{8}{11} + \frac{5}{11} = \frac{8+5}{11} = \frac{13}{11} = 1\frac{2}{11} \)
- 18) \( 7\frac{3}{10} + 3\frac{7}{10} = (7+3) + \frac{3+7}{10} = 10 + \frac{10}{10} = 10 + 1 = 11 \)
- 19) \( 7\frac{8}{19} + 1\frac{13}{19} = (7+1) + \frac{8+13}{19} = 8 + \frac{21}{19} = 8 + 1\frac{2}{19} = 9\frac{2}{19} \)
- 20) \( \frac{9}{14} + 5\frac{11}{14} = 5 + \frac{9+11}{14} = 5 + \frac{20}{14} = 5 + 1\frac{6}{14} = 6\frac{6}{14} = 6\frac{3}{7} \)
- 21) \( 7\frac{1}{8} + \frac{3}{8} = 7 + \frac{1+3}{8} = 7 + \frac{4}{8} = 7\frac{4}{8} = 7\frac{1}{2} \)
- 22) \( 31\frac{1}{9} + 12\frac{8}{9} = (31+12) + \frac{1+8}{9} = 43 + \frac{9}{9} = 43 + 1 = 44 \)
- 23) \( 9\frac{7}{12} + \frac{1}{12} = 9 + \frac{7+1}{12} = 9 + \frac{8}{12} = 9\frac{8}{12} = 9\frac{2}{3} \)
- 24) \( 17\frac{9}{10} + 50\frac{7}{10} = (17+50) + \frac{9+7}{10} = 67 + \frac{16}{10} = 67 + 1\frac{6}{10} = 68\frac{6}{10} = 68\frac{3}{5} \)
Ответ:
- 13) \( 1\frac{3}{28} \)
- 14) \( 7\frac{1}{5} \)
- 15) \( 1\frac{4}{13} \)
- 16) \( 9\frac{8}{13} \)
- 17) \( 1\frac{2}{11} \)
- 18) 11
- 19) \( 9\frac{2}{19} \)
- 20) \( 6\frac{3}{7} \)
- 21) \( 7\frac{1}{2} \)
- 22) 44
- 23) \( 9\frac{2}{3} \)
- 24) \( 68\frac{3}{5} \)
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