\[ -\frac{7}{5} \cdot (\frac{3}{5} y + \frac{2}{3}) = \frac{2}{5} - 2y \]
\[ -\frac{7}{5} \cdot \frac{3}{5} y - \frac{7}{5} \cdot \frac{2}{3} = \frac{2}{5} - 2y \]
\[ -\frac{21}{25} y - \frac{14}{15} = \frac{2}{5} - 2y \]
\[ 2y - \frac{21}{25} y = \frac{2}{5} + \frac{14}{15} \]
\[ \frac{50}{25} y - \frac{21}{25} y = \frac{6}{15} + \frac{14}{15} \]
\[ \frac{29}{25} y = \frac{20}{15} \]
\[ \frac{29}{25} y = \frac{4}{3} \]
\[ y = \frac{4}{3} : \frac{29}{25} = \frac{4}{3} \cdot \frac{25}{29} \]
\[ y = \frac{100}{87} \]
Ответ: \( \frac{100}{87} \)