\(a\) \(4^{-2} = \frac{1}{4^2} = \frac{1}{16}\)
\(б\) \((-3)^{-3} = \frac{1}{(-3)^3} = \frac{1}{-27} = -\frac{1}{27}\)
\(\text{г}) \((-1)^{-20} = \frac{1}{(-1)^{20}} = \frac{1}{1} = 1\)
\(е\) \((-3)^{-3} = \frac{1}{(-3)^3} = \frac{1}{-27} = -\frac{1}{27}\)
\(ж\) \(1^{-\frac{1}{2}} = \frac{1}{1^{\frac{1}{2}}} = \frac{1}{1} = 1\)
Ответ: а) ±/16; б) -1/27; г) 1; е) -1/27; ж) 1.