Ответ:
- \(\frac{5}{6}-\frac{3}{22}=\frac{55}{66}-\frac{9}{66}=\frac{46}{66}=\frac{23}{33}\).
- \(0,75-\left(\frac{3}{16}+\frac{1}{24}\right)=\frac{3}{4}-\left(\frac{9}{48}+\frac{2}{48}\right)=\frac{36}{48}-\frac{11}{48}=\frac{25}{48}\).
- \(\frac{9}{16}+\left(0,25-\frac{5}{24}\right)=\frac{9}{16}+\left(\frac{6}{24}-\frac{5}{24}\right)=\frac{27}{48}+\frac{2}{48}=\frac{29}{48}\).
- \(0,88-\frac{2}{15}=\frac{22}{25}-\frac{2}{15}=\frac{66}{75}-\frac{10}{75}=\frac{56}{75}\).
- Правая часть выражения на фотографии обрезана. Если записано именно \(\left(\frac{1}{6}+\frac{5}{18}\right)-\left(\frac{1}{18}+\frac{1}{24}\right)\), то:
\(\frac{1}{6}+\frac{5}{18}=\frac{3}{18}+\frac{5}{18}=\frac{4}{9}\),
\(\frac{1}{18}+\frac{1}{24}=\frac{4}{72}+\frac{3}{72}=\frac{7}{72}\),
\(\frac{4}{9}-\frac{7}{72}=\frac{32}{72}-\frac{7}{72}=\frac{25}{72}\). - \(4-2\frac{4}{7}=4-\frac{18}{7}=\frac{28}{7}-\frac{18}{7}=\frac{10}{7}=1\frac{3}{7}\).
- \(2,5+1\frac{2}{3}-3\frac{1}{6}=\frac{5}{2}+\frac{5}{3}-\frac{19}{6}=\frac{15+10-19}{6}=1\).
- \(0,36-\frac{9}{75}+\frac{2}{15}=\frac{9}{25}-\frac{3}{25}+\frac{2}{15}=\frac{6}{25}+\frac{2}{15}=\frac{18}{75}+\frac{10}{75}=\frac{28}{75}\).
Ответ: а) \(\frac{23}{33}\); б) \(\frac{25}{48}\); в) \(\frac{29}{48}\); г) \(\frac{56}{75}\); д) \(\frac{25}{72}\) при указанной записи; е) \(1\frac{3}{7}\); ж) \(1\); з) \(\frac{28}{75}\).
