Вопрос:

1. Вычислить: 1) \(0,9\cdot\sqrt{2500}\); 2) \(\frac{1}{14}\sqrt{196}-10\sqrt{0,01}\); 3) \(\frac{6}{7}\cdot\sqrt{\frac{13}{36}}\); 4) \(10\sqrt{3,24}-\sqrt{256}\); 5) \(\frac{1}{2}\cdot\sqrt{196}+1,5\cdot\sqrt{0,36}\); 6) \(5-\frac{1}{7}\cdot\sqrt{\frac{27}{169}}\).

Ответ:

  1. \(0,9\cdot\sqrt{2500}=0,9\cdot50=45\).
  2. \(\frac{1}{14}\sqrt{196}-10\sqrt{0,01}=\frac{14}{14}-10\cdot0,1=1-1=0\).
  3. \(\frac{6}{7}\cdot\sqrt{\frac{13}{36}}=\frac{6}{7}\cdot\frac{\sqrt{13}}{6}=\frac{\sqrt{13}}{7}\).
  4. \(10\sqrt{3,24}-\sqrt{256}=10\cdot1,8-16=18-16=2\).
  5. \(\frac{1}{2}\cdot\sqrt{196}+1,5\cdot\sqrt{0,36}=\frac{1}{2}\cdot14+1,5\cdot0,6=7+0,9=7,9\).
  6. \(5-\frac{1}{7}\cdot\sqrt{\frac{27}{169}}=5-\frac{1}{7}\cdot\frac{3\sqrt3}{13}=5-\frac{3\sqrt3}{91}\).

Ответ: 1) 45; 2) 0; 3) \(\frac{\sqrt{13}}{7}\); 4) 2; 5) 7,9; 6) \(5-\frac{3\sqrt3}{91}\).