1. Решите уравнение: 2) б) \(\frac{x+2}{4} = \frac{3x-5}{5}\); В) \(\frac{7-x}{6} = \frac{19x-11}{8}\)

Решение:

1. 2) б)
1. \(\frac{x+2}{4} = \frac{3x-5}{5}\)
2. \(5(x+2) = 4(3x-5)\)
3. \(5x + 10 = 12x - 20\)
4. \(10 + 20 = 12x - 5x\)
5. \(30 = 7x\)
6. \(x = \frac{30}{7}\)
2. В)
1. \(\frac{7-x}{6} = \frac{19x-11}{8}\)
2. \(8(7-x) = 6(19x-11)\)
3. \(56 - 8x = 114x - 66\)
4. \(56 + 66 = 114x + 8x\)
5. \(122 = 122x\)
6. \(x = \frac{122}{122}\)
7. \(x = 1\)

Ответ: 2) б) \(x = \frac{30}{7}\); В) \(x = 1\).