1 Найдите разность:

Решение:

1. \( \frac{4}{5} - \frac{3}{4} = \frac{4 \cdot 4 - 3 \cdot 5}{5 \cdot 4} = \frac{16 - 15}{20} = \frac{1}{20} \)
2. \( \frac{2}{3} - \frac{1}{7} = \frac{2 \cdot 7 - 1 \cdot 3}{3 \cdot 7} = \frac{14 - 3}{21} = \frac{11}{21} \)
3. \( \frac{5}{9} - \frac{1}{3} = \frac{5 \cdot 1 - 1 \cdot 3}{9} = \frac{5 - 3}{9} = \frac{2}{9} \)
4. \( \frac{5}{6} - \frac{1}{2} = \frac{5 \cdot 1 - 1 \cdot 3}{6} = \frac{5 - 3}{6} = \frac{2}{6} = \frac{1}{3} \)
5. \( \frac{2}{3} - \frac{1}{7} = \frac{2 \cdot 7 - 1 \cdot 3}{3 \cdot 7} = \frac{14 - 3}{21} = \frac{11}{21} \)
6. \( \frac{10}{7} - \frac{3}{2} = \frac{10 \cdot 2 - 3 \cdot 7}{7 \cdot 2} = \frac{20 - 21}{14} = -\frac{1}{14} \)
7. \( \frac{5}{12} - 0 = \frac{5}{12} \)
8. \( \frac{15}{36} - ( \frac{1}{3} - \frac{1}{12} ) = \frac{15}{36} - \frac{1 \cdot 4 - 1 \cdot 1}{12} = \frac{15}{36} - \frac{4 - 1}{12} = \frac{15}{36} - \frac{3}{12} = \frac{15}{36} - \frac{3 \cdot 3}{12 \cdot 3} = \frac{15}{36} - \frac{9}{36} = \frac{15-9}{36} = \frac{6}{36} = \frac{1}{6} \)