Вопрос:

1.314. Решите уравнение:

Ответ:

1.314. Решение уравнений:


А) \( 7(x-9) = 14 \)

\( x-9 = \frac{14}{7} \)

\( x-9 = 2 \)

\( x = 2+9 \)

\( x = 11 \)


Б) \( 8(x-11) = 64 \)

\( x-11 = \frac{64}{8} \)

\( x-11 = 8 \)

\( x = 8+11 \)

\( x = 19 \)


В) \( 3(x-1) = 3 \)

\( x-1 = \frac{3}{3} \)

\( x-1 = 1 \)

\( x = 1+1 \)

\( x = 2 \)


Г) \( 13(x-2) = 26 \)

\( x-2 = \frac{26}{13} \)

\( x-2 = 2 \)

\( x = 2+2 \)

\( x = 4 \)


Д) \( 0,3(x-1) = 12 \)

\( x-1 = \frac{12}{0,3} \)

\( x-1 = 40 \)

\( x = 40+1 \)

\( x = 41 \)


Е) \( 0,7(x-7) = 42 \)

\( x-7 = \frac{42}{0,7} \)

\( x-7 = 60 \)

\( x = 60+7 \)

\( x = 67 \)


Ё) \( \frac{3}{7}(x-8) = 12 \)

\( x-8 = 12 \cdot \frac{7}{3} \)

\( x-8 = 4 \cdot 7 \)

\( x-8 = 28 \)

\( x = 28+8 \)

\( x = 36 \)


Ж) \( \frac{5}{9}(x-1) = 15 \)

\( x-1 = 15 \cdot \frac{9}{5} \)

\( x-1 = 3 \cdot 9 \)

\( x-1 = 27 \)

\( x = 27+1 \)

\( x = 28 \)


И) \( \frac{10}{11}(x-8) = 0,1 \)

\( x-8 = 0,1 \cdot \frac{11}{10} \)

\( x-8 = \frac{1}{10} \cdot \frac{11}{10} \)

\( x-8 = \frac{11}{100} \)

\( x = 8 + \frac{11}{100} \)

\( x = 8 \frac{11}{100} = 8,11 \)


Й) \( \frac{5}{7}(x-5) = 1,4 \)

\( x-5 = 1,4 \cdot \frac{7}{5} \)

\( x-5 = \frac{14}{10} \cdot \frac{7}{5} \)

\( x-5 = \frac{7}{5} \cdot \frac{7}{5} \)

\( x-5 = \frac{49}{25} \)

\( x = 5 + \frac{49}{25} \)

\( x = \frac{125+49}{25} \)

\( x = \frac{174}{25} = 6,96 \)


К) \( 5(x+3) = 22 \)

\( x+3 = \frac{22}{5} \)

\( x+3 = 4,4 \)

\( x = 4,4-3 \)

\( x = 1,4 \)


Л) \( 7(x+2) = 20 \)

\( x+2 = \frac{20}{7} \)

\( x = \frac{20}{7} - 2 \)

\( x = \frac{20-14}{7} \)

\( x = \frac{6}{7} \)


Ответ: А) 11; Б) 19; В) 2; Г) 4; Д) 41; Е) 67; Ё) 36; Ж) 28; И) 8,11; Й) 6,96; К) 1,4; Л) 6/7.