(1/2)4-(1/4)2

$$\(\left\)\(\frac{1}{2}\right\)^4 - \(\left\)\(\frac{1}{4}\right\)^2 = \(\frac{1^4}{2^4}\) - \(\frac{1^2}{4^2}\) = \(\frac{1}{16}\) - \(\frac{1}{16}\) = 0

Ответ: 0