Решение:
\( 1\frac{1}{5} : \left( \frac{17}{40} + 0,6 - 0,005 \right) = \frac{6}{5} : \left( \frac{17}{40} + \frac{6}{10} - \frac{5}{1000} \right) \)
\( \frac{17}{40} + \frac{3}{5} - \frac{1}{200} = \frac{17 \cdot 5 + 3 \cdot 40 - 1}{200} = \frac{85 + 120 - 1}{200} = \frac{204}{200} = \frac{51}{50} \)
\( \frac{6}{5} : \frac{51}{50} = \frac{6}{5} \cdot \frac{50}{51} = \frac{6 \cdot 10}{51} = \frac{60}{51} = \frac{20}{17} \)
\( 4,75 + 7\frac{1}{2} = 4.75 + 7.5 = 12.25 \)
\( \frac{20}{17} \cdot 1.7 + 12.25 : 0.25 \)
\( \frac{20}{17} \cdot \frac{17}{10} = \frac{20}{10} = 2 \)
\( 12.25 : 0.25 = 49 \)
\( 2 + 49 = 51 \)
Ответ: 51