№2. Выполни действия: 5) \(\frac{9}{34} + \frac{17}{34} - \frac{13}{34}\), 3) \(1 - \frac{13}{30}\), 4) \(7\frac{5}{9} - 4\frac{4}{9}\); 5) \(\frac{4}{10} \cdot \frac{20}{24}\). 6) \(\frac{18}{35}:\frac{9}{14}\) 6) \(4\frac{5}{41} - 2\frac{3}{41} + 6\frac{7}{41}\);

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Вопрос:

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Accepted Answer

Краткое пояснение: Выполняем действия с дробями, соблюдая порядок операций.

\(\frac{9}{34} + \frac{17}{34} - \frac{13}{34} = \frac{9 + 17 - 13}{34} = \frac{26 - 13}{34} = \frac{13}{34}\)
\(1 - \frac{13}{30} = \frac{30}{30} - \frac{13}{30} = \frac{30 - 13}{30} = \frac{17}{30}\)
\(7\frac{5}{9} - 4\frac{4}{9} = (7 - 4) + (\frac{5}{9} - \frac{4}{9}) = 3 + \frac{1}{9} = 3\frac{1}{9}\)
\(\frac{4}{10} \cdot \frac{20}{24} = \frac{4 \cdot 20}{10 \cdot 24} = \frac{80}{240} = \frac{1}{3}\)
\(\frac{18}{35} : \frac{9}{14} = \frac{18}{35} \cdot \frac{14}{9} = \frac{18 \cdot 14}{35 \cdot 9} = \frac{2 \cdot 2}{5 \cdot 1} = \frac{4}{5}\)
\(4\frac{5}{41} - 2\frac{3}{41} + 6\frac{7}{41} = (4 - 2 + 6) + (\frac{5}{41} - \frac{3}{41} + \frac{7}{41}) = 8 + \frac{5 - 3 + 7}{41} = 8 + \frac{9}{41} = 8\frac{9}{41}\)

Ответ: 5) \(\frac{13}{34}\), 3) \(\frac{17}{30}\), 4) \(3\frac{1}{9}\); 5) \(\frac{1}{3}\). 6) \(\frac{4}{5}\) 6) \(8\frac{9}{41}\);