№16. Найди значение выражения:

1) \(|x| + |y|\), если \(x = 2\frac{5}{6}\), \(y = -1,3\) \(|2\frac{5}{6}| + |-1,3| = 2\frac{5}{6} + 1,3 = \frac{17}{6} + \frac{13}{10} = \frac{17*5}{6*5} + \frac{13*3}{10*3} = \frac{85}{30} + \frac{39}{30} = \frac{124}{30} = \frac{62}{15} = 4\frac{2}{15} \approx 4,13\) 2) \(|x| - |y|\), если \(x = -5,28\), \(y = -2,8\) \(|-5,28| - |-2,8| = 5,28 - 2,8 = 2,48\) 3) \(|x| \cdot |y|\), если \(x = -4,8\), \(y = -2\frac{1}{12}\) \(|-4,8| \cdot |-2\frac{1}{12}| = 4,8 \cdot 2\frac{1}{12} = 4,8 \cdot \frac{25}{12} = \frac{48}{10} \cdot \frac{25}{12} = \frac{4 \cdot 12}{10} \cdot \frac{25}{12} = \frac{4 \cdot 25}{10} = \frac{100}{10} = 10\) 4) \(|x| : |y|\), если \(x = -872,9\), \(y = 14,5\) \(|-872,9| : |14,5| = 872,9 : 14,5 = \frac{8729}{10} : \frac{145}{10} = \frac{8729}{10} \cdot \frac{10}{145} = \frac{8729}{145} = 60,2\)