⑤ $$(4-х)^2-х(х+1)$$ при $$х=-\frac{1}{9}$$

$$(4-x)^2 - x(x+1) = 16 - 8x + x^2 - x^2 - x = 16 - 9x$$

$$16 - 9(-\frac{1}{9}) = 16 + 1 = 17$$

Ответ: 17