1) 2 5/13 ⋅ 11/15 + 1 5/13 ⋅ 11/15; 2) 3 1/14 ⋅ 9/3 + 13/28 ⋅ 9/3 - 9/3 ⋅ 1 2/7.

1) $$2 \frac{5}{13} \cdot \frac{11}{15} + 1 \frac{5}{13} \cdot \frac{11}{15} = (2 \frac{5}{13} + 1 \frac{5}{13}) \cdot \frac{11}{15} = (2 + 1 + \frac{5}{13} + \frac{5}{13}) \cdot \frac{11}{15} = (3 + \frac{10}{13}) \cdot \frac{11}{15} = \frac{3 \cdot 13 + 10}{13} \cdot \frac{11}{15} = \frac{49}{13} \cdot \frac{11}{15} = \frac{49 \cdot 11}{13 \cdot 15} = \frac{539}{195} = 2 \frac{149}{195}$$

2) $$3 \frac{1}{14} \cdot \frac{9}{3} + \frac{13}{28} \cdot \frac{9}{3} - \frac{9}{3} \cdot 1 \frac{2}{7} = \frac{9}{3} \cdot (3 \frac{1}{14} + \frac{13}{28} - 1 \frac{2}{7}) = 3 \cdot (3 + \frac{1}{14} + \frac{13}{28} - 1 - \frac{2}{7}) = 3 \cdot (3 - 1 + \frac{1}{14} + \frac{13}{28} - \frac{2}{7}) = 3 \cdot (2 + \frac{1 \cdot 2}{14 \cdot 2} + \frac{13}{28} - \frac{2 \cdot 4}{7 \cdot 4}) = 3 \cdot (2 + \frac{2}{28} + \frac{13}{28} - \frac{8}{28}) = 3 \cdot (2 + \frac{2+13-8}{28}) = 3 \cdot (2 + \frac{7}{28}) = 3 \cdot (2 + \frac{1}{4}) = 3 \cdot 2 \frac{1}{4} = 3 \cdot \frac{9}{4} = \frac{3 \cdot 9}{4} = \frac{27}{4} = 6 \frac{3}{4}$$

Ответ: 1) 2 149/195; 2) 6 3/4