1) √(64a⁶)/(25b⁴) , a=2, b=1 2) √(121a⁸)/(b⁴) , a=2; b=3 3) √(144a¹⁰)/(36a⁶) , a=4; b=?

Решаем:

1. \(\sqrt{\frac{64a^6}{25b^4}}\) при \(a=2\), \(b=1\):
   \(\sqrt{\frac{64 \cdot 2^6}{25 \cdot 1^4}} = \sqrt{\frac{64 \cdot 64}{25}} = \sqrt{\frac{4096}{25}} = \frac{64}{5} = 12,8\)
2. \(\sqrt{\frac{121a^8}{b^4}}\) при \(a=2\), \(b=3\):
   \(\sqrt{\frac{121 \cdot 2^8}{3^4}} = \sqrt{\frac{121 \cdot 256}{81}} = \frac{11 \cdot 16}{9} = \frac{176}{9} = 19 \frac{5}{9} \approx 19,56\)
3. \(\sqrt{\frac{144a^{10}}{36a^6}}\) при \(a=4\), \(b=?\):
   \(\sqrt{\frac{144 \cdot 4^{10}}{36 \cdot 4^6}} = \sqrt{\frac{144 \cdot 4^4 \cdot 4^6}{36 \cdot 4^6}} = \sqrt{\frac{144 \cdot 4^4}{36}} = \sqrt{4 \cdot 4^4} = \sqrt{4 \cdot 256} = \sqrt{1024} = 32\)

Ответ: 1) 12,8; 2) \(19 \frac{5}{9} \approx 19,56\); 3) 32