13) √2 cos(2x-π/3)=1

13) √2 cos(2x - π/3) = 1

cos(2x - π/3) = 1/√2

2x - π/3 = ±arccos(1/√2) + 2πn, n ∈ Z

2x - π/3 = ±π/4 + 2πn, n ∈ Z

2x = π/3 ± π/4 + 2πn, n ∈ Z

x = π/6 ± π/8 + πn, n ∈ Z

x = (4π ± 3π)/24 + πn, n ∈ Z

x₁ = 7π/24 + πn, n ∈ Z

x₂ = π/24 + πn, n ∈ Z

Ответ: x₁ = 7π/24 + πn, n ∈ Z; x₂ = π/24 + πn, n ∈ Z