2^(2-log₂5) + 0,5^(log₂5) =

Используем свойство степеней: a^(b-c) = a^b / a^c и a^(logₐ x) = x. Также, 0.5 = 1/2 = 2⁻¹. 2^(2 - log₂ 5) + 0.5^(log₂ 5) = 2² / 2^(log₂ 5) + (2⁻¹)^(log₂ 5) = 4 / 5 + (2^(log₂ 5))⁻¹ = 4/5 + (5)⁻¹ = 4/5 + 1/5 = 5/5 = 1