10) $$2\sqrt{3}-4\sqrt{48} + \sqrt{12}$$

$$2\sqrt{3}-4\sqrt{48} + \sqrt{12} = 2\sqrt{3} - 4\sqrt{16 \cdot 3} + \sqrt{4 \cdot 3} = 2\sqrt{3} - 4 \cdot 4\sqrt{3} + 2\sqrt{3} = 2\sqrt{3} - 16\sqrt{3} + 2\sqrt{3} = (2 - 16 + 2)\sqrt{3} = -12\sqrt{3}$$

Ответ: $$-12\sqrt{3}$$