2) 4\frac{1}{2} \cdot 2\frac{2}{3} - 12\frac{1}{4} : \frac{2}{3} + 3\frac{3}{8} + 2\frac{3}{4} =

$$4\frac{1}{2} \cdot 2\frac{2}{3} - 12\frac{1}{4} : \frac{2}{3} + 3\frac{3}{8} + 2\frac{3}{4} = \frac{9}{2} \cdot \frac{8}{3} - \frac{49}{4} : \frac{2}{3} + \frac{27}{8} + \frac{11}{4} = $$ $$\frac{72}{6} - \frac{49}{4} \cdot \frac{3}{2} + \frac{27}{8} + \frac{22}{8} = 12 - \frac{147}{8} + \frac{49}{8} = $$ $$\frac{96}{8} - \frac{147}{8} + \frac{49}{8} = \frac{96-147+49}{8} = \frac{-2}{8} = -\frac{1}{4}$$ Ответ: $$- \frac{1}{4}$$