15)\(2\frac{5}{6}-\frac{3}{4}-1\frac{1}{10}+\frac{8}{15}\)⋅4\frac{1}{2}⋅\(1\frac{5}{12}-\frac{1}{2}\)=

Ответ: 5$$\frac{251}{480}$$

1. \(2\frac{5}{6}-\frac{3}{4}=2\frac{10}{12}-\frac{9}{12}=2\frac{1}{12}\)
2. \(2\frac{1}{12}-1\frac{1}{10}=\frac{25}{12}-\frac{11}{10}=\frac{125}{60}-\frac{66}{60}=\frac{59}{60}\)
3. \(\frac{59}{60}+\frac{8}{15}=\frac{59}{60}+\frac{32}{60}=\frac{91}{60}\)
4. \(1\frac{5}{12}-\frac{1}{2}=1\frac{5}{12}-\frac{6}{12}=\frac{11}{12}\)
5. \(\frac{91}{60}⋅4\frac{1}{2}=\frac{91}{60}⋅\frac{9}{2}=\frac{819}{120}=\frac{273}{40}=6\frac{33}{40}\)
6. \(6\frac{33}{40}⋅\frac{11}{12}=\frac{273}{40}⋅\frac{11}{12}=\frac{3003}{480}=6\frac{123}{480}=6\frac{41}{160}\)

Ответ: 5$$\frac{251}{480}$$