101. Выполните умножение: 2 вариант 4) 1$$\frac{1}{6}$$ · 1$$\frac{5}{7}$$; 6) 9$$\frac{3}{8}$$· 2$$\frac{2}{5}$$; ⅱ) 4$$\frac{5}{12}$$·$$\frac{6}{53}$$; г) 2$$\frac{5}{11}$$· 1$$\frac{19}{36}$$. 105. Найдите значение выражения: 4) (6$$\frac{1}{8}$$-2$$\frac{11}{14}$$) · 1$$\frac{8}{13}$$· 1$$\frac{3}{5}$$; r) (4$$\frac{1}{3}$$-3$$\frac{4}{9}$$)$$^2$$· (2$$\frac{1}{4}$$)$$^2$$; a) (2$$\frac{7}{15}$$+1$$\frac{7}{12}$$)· 1$$\frac{1}{9}$$-1$$\frac{7}{8}$$; д) (5$$\frac{8}{15}$$-4$$\frac{7}{10}$$)· 2$$\frac{2}{3}$$-$$\frac{5}{9}$$; 4) (4$$\frac{3}{10}$$-3$$\frac{3}{5}$$·$$\frac{5}{12}$$)·$$\frac{5}{6}$$; е) ($$\frac{5}{24}$$+$$\frac{5}{16}$$)· (1$$\frac{2}{3}$$-$$\frac{3}{5}$$)· 1$$\frac{4}{5}$$ 109. Найдите значение выражения: a) (3$$\frac{3}{11}$$· 1$$\frac{2}{9}$$-2$$\frac{3}{8}$$)·$$\frac{16}{39}$$; 6) ($$\frac{9}{16}$$+4$$\frac{2}{3}$$·$$\frac{9}{56}$$)· 1$$\frac{1}{7}$$

Решим данные примеры: 101. Выполните умножение: а) $$1\frac{1}{6} \cdot 1\frac{5}{7} = \frac{7}{6} \cdot \frac{12}{7} = \frac{7 \cdot 12}{6 \cdot 7} = \frac{1 \cdot 2}{1 \cdot 1} = 2$$ б) $$9\frac{3}{8} \cdot 2\frac{2}{5} = \frac{75}{8} \cdot \frac{12}{5} = \frac{75 \cdot 12}{8 \cdot 5} = \frac{15 \cdot 3}{2 \cdot 1} = \frac{45}{2} = 22\frac{1}{2}$$ в) $$4\frac{5}{12} \cdot \frac{6}{53} = \frac{53}{12} \cdot \frac{6}{53} = \frac{53 \cdot 6}{12 \cdot 53} = \frac{1 \cdot 1}{2 \cdot 1} = \frac{1}{2}$$ г) $$2\frac{5}{11} \cdot 1\frac{19}{36} = \frac{27}{11} \cdot \frac{55}{36} = \frac{27 \cdot 55}{11 \cdot 36} = \frac{3 \cdot 5}{1 \cdot 4} = \frac{15}{4} = 3\frac{3}{4}$$ 105. Найдите значение выражения: а) $$(6\frac{1}{8} - 2\frac{11}{14}) \cdot 1\frac{8}{13} \cdot 1\frac{3}{5} = (\frac{49}{8} - \frac{39}{14}) \cdot \frac{21}{13} \cdot \frac{8}{5} = (\frac{343}{56} - \frac{156}{56}) \cdot \frac{21}{13} \cdot \frac{8}{5} = \frac{187}{56} \cdot \frac{21}{13} \cdot \frac{8}{5} = \frac{187 \cdot 21 \cdot 8}{56 \cdot 13 \cdot 5} = \frac{11 \cdot 3 \cdot 1}{1 \cdot 1 \cdot 5} = \frac{33}{5} = 6\frac{3}{5}$$ г) $$(4\frac{1}{3}-3\frac{4}{9})^2 \cdot (2\frac{1}{4})^2 = (\frac{13}{3} - \frac{31}{9})^2 \cdot (\frac{9}{4})^2 = (\frac{39}{9} - \frac{31}{9})^2 \cdot \frac{81}{16} = (\frac{8}{9})^2 \cdot \frac{81}{16} = \frac{64}{81} \cdot \frac{81}{16} = \frac{64 \cdot 81}{81 \cdot 16} = \frac{4 \cdot 1}{1 \cdot 1} = 4$$ б) $$(2\frac{7}{15} + 1\frac{7}{12}) \cdot 1\frac{1}{9} - 1\frac{7}{8} = (\frac{37}{15} + \frac{19}{12}) \cdot \frac{10}{9} - \frac{15}{8} = (\frac{148}{60} + \frac{95}{60}) \cdot \frac{10}{9} - \frac{15}{8} = \frac{243}{60} \cdot \frac{10}{9} - \frac{15}{8} = \frac{243 \cdot 10}{60 \cdot 9} - \frac{15}{8} = \frac{27 \cdot 1}{6 \cdot 1} - \frac{15}{8} = \frac{9}{2} - \frac{15}{8} = \frac{36}{8} - \frac{15}{8} = \frac{21}{8} = 2\frac{5}{8}$$ д) $$(5\frac{8}{15} - 4\frac{7}{10}) \cdot 2\frac{2}{3} - \frac{5}{9} = (\frac{83}{15} - \frac{47}{10}) \cdot \frac{8}{3} - \frac{5}{9} = (\frac{166}{30} - \frac{141}{30}) \cdot \frac{8}{3} - \frac{5}{9} = \frac{25}{30} \cdot \frac{8}{3} - \frac{5}{9} = \frac{5}{6} \cdot \frac{8}{3} - \frac{5}{9} = \frac{5 \cdot 8}{6 \cdot 3} - \frac{5}{9} = \frac{5 \cdot 4}{3 \cdot 3} - \frac{5}{9} = \frac{20}{9} - \frac{5}{9} = \frac{15}{9} = \frac{5}{3} = 1\frac{2}{3}$$ в) $$(4\frac{3}{10} - 3\frac{3}{5} \cdot \frac{5}{12}) \cdot \frac{5}{6} = (\frac{43}{10} - \frac{18}{5} \cdot \frac{5}{12}) \cdot \frac{5}{6} = (\frac{43}{10} - \frac{3}{1} \cdot \frac{1}{2}) \cdot \frac{5}{6} = (\frac{43}{10} - \frac{3}{2}) \cdot \frac{5}{6} = (\frac{43}{10} - \frac{15}{10}) \cdot \frac{5}{6} = \frac{28}{10} \cdot \frac{5}{6} = \frac{14}{5} \cdot \frac{5}{6} = \frac{14 \cdot 5}{5 \cdot 6} = \frac{7 \cdot 1}{1 \cdot 3} = \frac{7}{3} = 2\frac{1}{3}$$ е) $$(\frac{5}{24} + \frac{5}{16}) \cdot (1\frac{2}{3} - \frac{3}{5}) \cdot 1\frac{4}{5} = (\frac{10}{48} + \frac{15}{48}) \cdot (\frac{5}{3} - \frac{3}{5}) \cdot \frac{9}{5} = \frac{25}{48} \cdot (\frac{25}{15} - \frac{9}{15}) \cdot \frac{9}{5} = \frac{25}{48} \cdot \frac{16}{15} \cdot \frac{9}{5} = \frac{25 \cdot 16 \cdot 9}{48 \cdot 15 \cdot 5} = \frac{5 \cdot 1 \cdot 3}{3 \cdot 3 \cdot 1} = \frac{5}{3} = 1\frac{2}{3}$$ 109. Найдите значение выражения: а) $$(3\frac{3}{11} \cdot 1\frac{2}{9} - 2\frac{3}{8}) \cdot \frac{16}{39} = (\frac{36}{11} \cdot \frac{11}{9} - \frac{19}{8}) \cdot \frac{16}{39} = (\frac{36 \cdot 11}{11 \cdot 9} - \frac{19}{8}) \cdot \frac{16}{39} = (\frac{4 \cdot 1}{1 \cdot 1} - \frac{19}{8}) \cdot \frac{16}{39} = (4 - \frac{19}{8}) \cdot \frac{16}{39} = (\frac{32}{8} - \frac{19}{8}) \cdot \frac{16}{39} = \frac{13}{8} \cdot \frac{16}{39} = \frac{13 \cdot 16}{8 \cdot 39} = \frac{1 \cdot 2}{1 \cdot 3} = \frac{2}{3}$$ б) $$(\frac{9}{16} + 4\frac{2}{3} \cdot \frac{9}{56}) \cdot 1\frac{1}{7} = (\frac{9}{16} + \frac{14}{3} \cdot \frac{9}{56}) \cdot \frac{8}{7} = (\frac{9}{16} + \frac{1}{1} \cdot \frac{3}{4}) \cdot \frac{8}{7} = (\frac{9}{16} + \frac{3}{4}) \cdot \frac{8}{7} = (\frac{9}{16} + \frac{12}{16}) \cdot \frac{8}{7} = \frac{21}{16} \cdot \frac{8}{7} = \frac{21 \cdot 8}{16 \cdot 7} = \frac{3 \cdot 1}{2 \cdot 1} = \frac{3}{2} = 1\frac{1}{2}