Вопрос:

ВАРИАНТЫ ПРАКТИЧЕСКОЙ РАБОТЫ

Ответ:

123456
a$$3^4 = 81$$$$(\frac{1}{2})^5 = \frac{1}{32}$$$$6^{-2} = \frac{1}{36}$$$$(\frac{3}{2})^{-3} = (\frac{2}{3})^3 = \frac{8}{27}$$$$(\sqrt{7})^2 = 7$$$$164$$
b$$4^3 = 64$$$$(\frac{2}{3})^3 = \frac{8}{27}$$$$2^{-4} = \frac{1}{16}$$$$(\frac{2}{5})^{-2} = (\frac{5}{2})^2 = \frac{25}{4} = 6.25$$$$(\sqrt{2})^8 = 2^4 = 16$$$$642$$
c$$2^4 = 16$$$$(\frac{3}{5})^2 = \frac{9}{25}$$$$3^{-3} = \frac{1}{27}$$$$(\frac{3}{4})^{-3} = (\frac{4}{3})^3 = \frac{64}{27}$$$$(\sqrt{5})^4 = 5^2 = 25$$$$83$$
d$$5^3 = 125$$$$(\frac{3}{2})^1 = \frac{3}{2} = 1.5$$$$5^{-1} = \frac{1}{5}$$$$(\frac{1}{2})^{-5} = 2^5 = 32$$$$(\sqrt{2})^{10} = 2^5 = 32$$$$325$$
e$$2^5 = 32$$$$(\frac{4}{3})^3 = \frac{64}{27}$$$$3^{-4} = \frac{1}{81}$$$$(\frac{1}{3})^{-1} = 3$$$$(\sqrt{6})^4 = 6^2 = 36$$$$273$$
f$$3^3 = 27$$$$(\frac{1}{3})^4 = \frac{1}{81}$$$$2^{-3} = \frac{1}{8}$$$$(\frac{2}{3})^{-4} = (\frac{3}{2})^4 = \frac{81}{16}$$$$(\sqrt{2})^6 = 2^3 = 8$$$$814$$
g$$5^0 = 1$$$$(\frac{2}{5})^3 = \frac{8}{125}$$$$7^{-2} = \frac{1}{49}$$$$(\frac{3}{4})^{-1} = \frac{4}{3}$$$$(\sqrt{3})^4 = 3^2 = 9$$$$643$$
h$$2^3 = 8$$$$(\frac{3}{4})^2 = \frac{9}{16}$$$$4^{-1} = \frac{1}{4}$$$$(\frac{1}{2})^{-4} = 2^4 = 16$$$$(\sqrt{5})^0 = 1$$$$252$$
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