$$\frac{64^{-2} \cdot 2^{5}}{1024^{0} \cdot 32^{-3}} = \frac{(2^6)^{-2} \cdot 2^{5}}{1 \cdot (2^5)^{-3}} = \frac{2^{-12} \cdot 2^{5}}{2^{-15}} = \frac{2^{-7}}{2^{-15}} = 2^{-7-(-15)} = 2^{-7+15} = 2^8$$
Ответ: $$2^8$$