Для решения этой задачи необходимо построить таблицы истинности для каждого логического выражения.
a) B & (A v B)
| A |
B |
A v B |
B & (A v B) |
| И |
И |
И |
И |
| И |
Л |
И |
Л |
| Л |
И |
И |
И |
| Л |
Л |
Л |
Л |
б) A & (B v $$\overline{B}$$)
| A |
B |
$$\overline{B}$$ |
B v $$\overline{B}$$ |
A & (B v $$\overline{B}$$) |
| И |
И |
Л |
И |
И |
| И |
Л |
И |
И |
И |
| Л |
И |
Л |
И |
Л |
| Л |
Л |
И |
И |
Л |
в) A & (A v B v C)
| A |
B |
C |
A v B v C |
A & (A v B v C) |
| И |
И |
И |
И |
И |
| И |
И |
Л |
И |
И |
| И |
Л |
И |
И |
И |
| И |
Л |
Л |
И |
И |
| Л |
И |
И |
И |
Л |
| Л |
И |
Л |
И |
Л |
| Л |
Л |
И |
И |
Л |
| Л |
Л |
Л |
Л |
Л |
г) $$\overline{(A v B v C)}$$
| A |
B |
C |
A v B v C |
$$\overline{(A v B v C)}$$ |
| И |
И |
И |
И |
Л |
| И |
И |
Л |
И |
Л |
| И |
Л |
И |
И |
Л |
| И |
Л |
Л |
И |
Л |
| Л |
И |
И |
И |
Л |
| Л |
И |
Л |
И |
Л |
| Л |
Л |
И |
И |
Л |
| Л |
Л |
Л |
Л |
И |