Найдите сумму: 1) $$5\frac{7}{8}+6\frac{3}{10}$$; 2) $$6\frac{3}{8}+2\frac{5}{9}$$; 3) $$1\frac{8}{21}+4\frac{3}{14}+2\frac{2}{7}$$.

Question

Вопрос:

Ответ:

Accepted Answer

$$5\frac{7}{8}+6\frac{3}{10} = 5\frac{35}{40}+6\frac{12}{40} = 11\frac{47}{40} = 12\frac{7}{40}$$
Ответ: $$12\frac{7}{40}$$
$$6\frac{3}{8}+2\frac{5}{9} = 6\frac{27}{72}+2\frac{40}{72} = 8\frac{67}{72}$$
Ответ: $$8\frac{67}{72}$$
$$1\frac{8}{21}+4\frac{3}{14}+2\frac{2}{7} = 1\frac{16}{42}+4\frac{9}{42}+2\frac{12}{42} = 7\frac{37}{42}$$
Ответ: $$7\frac{37}{42}$$