2) $$1^{-0,43} - (0,008)^{\frac{1}{3}} + (15,1)^{0} = 1 - (0,2)^{3 \cdot \frac{1}{3}} + 1 = 1 - 0,2 + 1 = 2 - 0,2 = \textbf{1,8}$$
4) $$(0,125)^{\frac{1}{3}} + (\frac{3}{4})^{2} - (1,85)^{0} = (\frac{1}{8})^{\frac{1}{3}} + \frac{9}{16} - 1 = (\frac{1}{2^{3}})^{\frac{1}{3}} + \frac{9}{16} - 1 = \frac{1}{2} + \frac{9}{16} - 1 = \frac{8}{16} + \frac{9}{16} - \frac{16}{16} = \frac{17}{16} - \frac{16}{16} = \textbf{\frac{1}{16}}$$
2) $$1,7 \cdot 10^{-6} \cdot 3 \cdot 10^{7} = 1,7 \cdot 3 \cdot 10^{-6+7} = 5,1 \cdot 10^{1} = \textbf{51}$$
4) $$6,4 \cdot 10^{5} : (1,6 \cdot 10^{7}) = \frac{6,4}{1,6} \cdot \frac{10^{5}}{10^{7}} = 4 \cdot 10^{5-7} = 4 \cdot 10^{-2} = 4 \cdot \frac{1}{100} = \textbf{0,04}$$