Выполним упрощение каждого выражения:
3)
$$\frac{4^7}{64} = \frac{(2^2)^7}{2^6} = \frac{2^{14}}{2^6} = 2^{14-6} = 2^8 = 256$$6)
$$\frac{27^5}{9^6} = \frac{(3^3)^5}{(3^2)^6} = \frac{3^{15}}{3^{12}} = 3^{15-12} = 3^3 = 27$$9)
$$\frac{21^4}{3^2 \cdot 7^3} = \frac{(3 \cdot 7)^4}{3^2 \cdot 7^3} = \frac{3^4 \cdot 7^4}{3^2 \cdot 7^3} = 3^{4-2} \cdot 7^{4-3} = 3^2 \cdot 7^1 = 9 \cdot 7 = 63$$12)
$$\frac{(7^2 \cdot 7^4)^5}{(7 \cdot 7^6)^4} = \frac{(7^{2+4})^5}{(7^{1+6})^4} = \frac{(7^6)^5}{(7^7)^4} = \frac{7^{6 \cdot 5}}{7^{7 \cdot 4}} = \frac{7^{30}}{7^{28}} = 7^{30-28} = 7^2 = 49$$15)
$$\frac{1}{2^{-7}} \cdot \frac{1}{2^9} = 2^7 \cdot 2^{-9} = 2^{7-9} = 2^{-2} = \frac{1}{2^2} = \frac{1}{4} = 0.25$$18)
$$\frac{2^{-5} \cdot 2^{-8}}{2^{-17}} = \frac{2^{-5-8}}{2^{-17}} = \frac{2^{-13}}{2^{-17}} = 2^{-13 - (-17)} = 2^{-13+17} = 2^4 = 16$$21)
$$\frac{(2^9)^{-3}}{2^{-29}} = \frac{2^{9 \cdot (-3)}}{2^{-29}} = \frac{2^{-27}}{2^{-29}} = 2^{-27 - (-29)} = 2^{-27+29} = 2^2 = 4$$